78) What is the boiling point of a solution of 0.1 mol of glucose in 200 ml of water?
b ^ = K 0.512dC / m ———- dC = degrees Celsius A. 100.06dC 100.13dC B. C. 100.26dC D. 100.5dC ps. see all my questions plzzz chemistry
D. 100.26 ° C Explanation: elevation boiling dilute solutions can be calculated from ΔTb Kb = Kb ∙ ∙ above ebulioscopic constant of the solvent, the factor i van't Hoff c solute molality, solute non-separation of solutes such as glucose dissolved in water i = 1 Assuming that the density of water is 1 kg 0.2 kg / L, you have water, forming the solution. Therefore, the molality is c = 0.1mol/0.2kg = 0.5m then: ∙ ΔTb = 0.512 ° C m / 1 ∙ 0.5 m = 0.256 ° C = °> Tb = Tb + ΔTb = 100 ° C + 0256 ° C = 100.256 ° C ≈ 100.26 ° C
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